Given that a, b, c, d, p and q are natural numbers such that a < b and d < c. It is also given that the following result holds true:
ab×dc=qp
Choose the correct option(s):
q > p
q < p
Given that a, b, c, d, p and q are natural numbers such that a<b and d<c. It is also given that the following result holds true:
Given that a, b, c, d, p and q are natural numbers such that a < b and d < c and q < p and given that ab×dc=qp holds true,Which of the following is/are true?
Let ABCD be a square and let points P on AB and Q on DC be such that DP = AQ. Prove that BP = CQ.