Given that AB - AC and - BOC -140- where O is the center of the circle- - ABC -A- 45-B- 55-C- 60-D- 50-E- 65-

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Angle Sum Property

Given that AB...

Question

Given that AB = AC and $∠$ BOC = $140^{\circ}$ where O is the center of the circle. $∠$ ABC =?

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Solution

The correct option is B

$∠$ BAC = $70^{\circ}$

Angle subtended by an arc at the centre is twice the angle subtended by it at any point.

Since, $Δ$ ABC is isosceles, $∠$ ABC = $∠$ ACB = $\frac{180^{\circ} - 70^{\circ}}{2}$

$∴$ $∠$ ABC = $55^{\circ}$

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Given that AB = AC and ∠BOC = 140∘ where O is the center of the circle. ∠ABC =?

The correct option is B ∠BAC = 70∘ Angle subtended by an arc at the centre is twice the angle subtended by it at any point. Since, Δ ABC is isosceles, ∠ABC = ∠ACB = 180∘−70∘2 ∴∠ABC = 55∘

Given that AB = AC and $∠$ BOC = $140^{\circ}$ where O is the center of the circle. $∠$ ABC =?

The correct option is B

$∠$ BAC = $70^{\circ}$

Angle subtended by an arc at the centre is twice the angle subtended by it at any point.

Since, $Δ$ ABC is isosceles, $∠$ ABC = $∠$ ACB = $\frac{180^{\circ} - 70^{\circ}}{2}$

$∴$ $∠$ ABC = $55^{\circ}$