Question

Given that ABCD is a trapezoid where $AD\parallel BC$. $AD=12\text{units}\&BC=16\text{units}$.
Height of the trapezoid is $13\text{units}$.
Find area of the trapezoid.

• A. $182$ square units
• B. $180$ square units
• C. $200$ square units
• D. $201$ square units

Answer 1

The correct option is A $182$ square units

Given,
BC = 16 unit
AD = 12 unit
Height of the trapezoid $=13$ unit
AD is parallel to BC

As we know,
Area of a trapezoid $=\frac{1}{2}\times$ (sum of the parallel sides)$\times h$

$=\frac{1}{2}\times (BC+AD)\times DE$

$=\frac{1}{2}\times (16+12)\times 13$

$=14\times 13$

$=182$ square units

Option (a) is correct.