Given that ai-0 and i belongs to a set of natural numbers- If a1- a2- a3- a2 n are in AP- then find the value of a1-a2 n-a1-a2-a2-a2 n-1-a2-a3-a n- a n-1-a n -a n -1A- n a1-a2 n-a1-an-1B- n-1-a1-an-1C- n-1D- n-1-a1-an-1

The correct option is A Let the AP be 1,2,3,4,5 At n=1, the AP = 1,2 a_1=1 and nbsp;a_2=2 The value of the expression =3/2.4 Only option (b) gives this va ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Quantitative Aptitude

Progressions

Given that ai...

Question

Given that a_i $>$ 0 and i belongs to a set of natural numbers. If $a_{1}, a_{2}, a_{3} . . . . . a_{2 n}$ are in AP, then find the value of $\frac{a_{1} + a_{2 n}}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{a_{2} + a_{2 n} - 1}{{\sqrt{a}}_{2} + \sqrt{a_{3}}} . . . . . . . . . . . . + \frac{a_{n} + a_{n + 1}}{\sqrt{a_{n}} + \sqrt{a_{n + 1}}}$

n-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

Let the AP be 1,2,3,4,5

At n=1, the AP = 1,2

$a_{1} = 1$ and $a_{2} = 2$

The value of the expression $= \frac{3}{2.4}$

Only option (b) gives this value

Suggest Corrections

Similar questions

Q. If

a_{r} > 0; \forall r, n \in N

and

a_{1}, a_{2}, a_{3}, . . . . . a_{2 n}

are in A.P, then

\frac{a_{1} + a_{2 n}}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{a_{2} + a_{2 n - 1}}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{a_{3} + a_{2 n - 2}}{\sqrt{a_{3}} + \sqrt{a_{4}}} + . . . + \frac{a_{n} + a_{n + 1}}{\sqrt{a_{n}} + \sqrt{a_{n + 1}}} =

Q. If

a_{r} > 0, r \in N

and

a_{1}, a_{2}, a_{3}, . . ., a_{2 n}

are in A.P. then

\frac{a_{1} + a_{2 n}}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{a_{2} + a_{2 n - 1}}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{a_{3} + a_{2 n - 2}}{\sqrt{a_{3}} + \sqrt{a_{4}}} + . . . + \frac{a_{n} + a_{n + 1}}{\sqrt{a_{n}} + \sqrt{a_{n + 1}}}

is equal to

Q. If

a_{r} > 0, r ϵ N

and

a_{1}

a_{2}

a_{3}

,...,

a_{2 n}

are in AP then

\frac{a_{1} + a_{2 n}}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{a_{2} + a_{2 n - 1}}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{a_{3} + a_{2 n - 2}}{\sqrt{a_{3}} + \sqrt{a_{4}}} + . . . + \frac{a_{n} + a_{n + 1}}{\sqrt{a_{n}} + \sqrt{a_{n + 1}}}

is equal to

Q. If

a_{1,} a_{2,} a_{3,} . . . . . . . . a_{2 n + 1}

are in A.P. then

\frac{a_{2 n + 1} - a_{1}}{a_{2 n + 1} + a_{1}} + \frac{a_{2 n + 1} - a_{2}}{a_{2 n + 1} + a_{2}} + . . . . . . + \frac{a_{2 n + 1} - a_{n}}{a_{2 n + 1} + a_{n}}

Q. If

a_{1}, a_{2}, a_{3}, . . . . a_{2 n + 1}

are in A.P. then

\frac{a_{2 n + 1} - a_{1}}{a_{2 n + 1} + a_{1}} + \frac{a_{2 n} - a_{2}}{a_{2 n} + a_{2}} + . . . + \frac{a_{n + 2} - a_{n}}{a_{n + 2} + a_{n}}

is equal to

Join BYJU'S Learning Program

Given that ai > 0 and i belongs to a set of natural numbers. If a1,a2,a3.....a2n are in AP, then find the value of a1+a2n√a1+√a2+a2+a2n−1√a2+√a3............+an+an+1√an+√an+1

The correct option is B Let the AP be 1,2,3,4,5 At n=1, the AP = 1,2 a1=1 and a2=2 The value of the expression =32.4 Only option (b) gives this value

The correct option is B

Let the AP be 1,2,3,4,5

At n=1, the AP = 1,2

$a_{1} = 1$ and $a_{2} = 2$

The value of the expression $= \frac{3}{2.4}$

Only option (b) gives this value