Question

Given that carbon $14\left(C_{14}\right)$ decays at a constant rate in such a way that it reduces to 50 % in 5568 years. Find the age of an old wooden piece in the carbon is only $12\frac{1}{2}$ % of the original.

Answer 1

the carbon 14 $\left(C_{14}\right)$ reduces to 50% in 5568 days then,

it will reduce to 25% in $\Rightarrow$(5568$\times 2)$ days

further it will reduce 12.5% in $\Rightarrow (5568\times 3)$

days = 16,704 days