Given that cos-m -n then tan- is equal to

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Trigonometric Ratios of Standard Angles

Given that co...

Question

Given that cos θ = ^m/_n then tanθ is equal to

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cos θ > 0, tan θ + sin θ = m

tan θ - sin θ = n

m^{2} - n^{2} = 4 \sqrt{m n}

tan θ = 4,

⎛ ⎜ ⎝ \frac{tan θ}{\frac{{sin}^{3} θ}{cos θ} + sin θ cos θ} ⎞ ⎟ ⎠

$I f c o s θ - t a n θ = s e c θ, t h e n, θ i s e q u a l t o$

cos (θ + ϕ) = m cos (θ - ϕ)

tan θ

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