Given that cosA =1/2 then the value of 2secA/1+tan squareA is.

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Solution

Answer :

Given : Cos A = $\frac{1}{2}$

We know : Cos $θ = \frac{A d j a c e n t}{H y p o t e n u s e} = \frac{1}{S e c θ}$
So,

Sec A = 2

We find value of :

$\frac{2 S e c A}{1 + \tan^{2} A} \Rightarrow \frac{2 S e c A}{S e c^{2} A} (W e k n o w S e c^{2} A - \tan^{2} A = 1) \Rightarrow \frac{2}{S e c A} \Rightarrow \frac{2}{2} \Rightarrow 1 (A n s)$

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