wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given that ddx(1+x2+x41+x+x2)=Ax+B.
What is the value of B?

A
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1
Given ddx(1+x2+x41+x+x2)=Ax+B ..... (i)
Now, ddx(x4+x2+1x2+x+1)=ddx((x2+x+1)(x2x+1)x2+x+1)
=ddx(x2x+1)
=2x1
Ax+B=2x1 ..... From (i)
Hence, B=1.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What is Binomial Expansion?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon