Question

Given that $\frac{4p+9q}{p}=\frac{5q}{p-q}$ and $p$ and $q$ are both positive. calculate $\frac{p}{q}$

• A. $\frac{1}{3}$
• B. $\frac{2}{3}$
• C. $\frac{3}{2}$
• D. $\frac{3}{5}$

Answer 1

The correct option is C $\frac{3}{2}$

Given

$\frac{4p+9q}{p}=\frac{5q}{p-q}$

or, $4p^2-4pq+9pq-9q^2=5pq$

or, $4p^2=9q^2$

or, $\frac{p}{q}=\frac{3}{2}$ [Since $p$ and $q$ are both positive]