Given that ${log}_{a} A = x$ is similar to $a^{x} = A$ .
If true then write 1 and if false then write 0

Open in App

Solution

Given, ${log}_{a} A = x$
$⟹ log$ of $x$ to the base $a$ is $A$
$⟹ A = a^{x}$ .

Suggest Corrections

Similar questions

30^{\circ}

t a n 2 x = \frac{2 t a n x}{1 - t a n^{2} x}

{log}_{3} m = x

{log}_{3} n = y

2 {log}_{3} A = 5 x - 3 y

A = \sqrt{\frac{m^{5}}{n^{3}}}

\frac{log 25}{log 5} = log x

x = 2

2 c o s^{2} A - 1 = 1 - 2 s i n^{2} A

s i n 3 A = 3 s i n A - 4 s i n^{3} A

Join BYJU'S Learning Program