CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given that x>0, x3 is equivalent to which of the following expressions?
I. x+x12
II. (x12)3
III. (x2)(x12)

A
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
I and II only
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
II and III only
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
I,II and III
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C II and III only
x3=(x3)12=x32
I.x+x12
This cannot be further simplified since there is addition between the two terms.
II.(x12)3=x12×3=x32
III.(x2)(x12)=x(212)=x32
Hence option C is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon