Question

Given that E and F are events such that P (E) = 0.6 P (F) = 0.3 and
P$(E\cap F)=0.2,find\left(\frac{E}{F}\right)andP\left(\frac{F}{E}\right).$

Answer 1

It is given that $P\left(E\right)=0.6,P\left(F\right)=0.3andP(E\cap F)=0.2$
$\therefore$ We know that $P\left(\frac{E}{F}\right)=\frac{P(E\cap F)}{P\left(F\right)}=\frac{0.2}{0.3}andP\left(\frac{F}{E}\right)=\frac{P(F\cap B)}{p\left(E\right)}=\frac{0.2}{0.6}=\frac{1}{3}$