Given that- EoFe2- Fe - -0-44 V- EoFe2- Fe3- - -0-77 V - If Fe2- - Fe3- and Fe solid are kept together- then-

The correct option is C Fe^3+ decreasesCell reaction, 2 #160;Fe^3+ + Fe ⟶ 3 #160;Fe^2+ E^o_cell = 0.77 ( 0.44) = 1.21 V ⇒ #160;Fe^ ...

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Electrochemical Series

Given that, ...

Question

Given that, $E_{F e^{2 +} / F e}^{o} = - 0.44 V, E_{F e^{2 +} / F e^{3 +}}^{o} = - 0.77 V$ . If $F e^{2 +}, F e^{3 +}$ and $F e$ solid are kept together, then:

F e^{3 +}

decreases

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F e^{3 +}

increases

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F e^{2 +}

decreases

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F e^{2 +}, F e^{3 +}

remain unchanged

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Solution

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Similar questions

E_{F e 2 + | F e}^{o} = - 0.44 V; E_{F e^{2 +} | F e^{3 +}}^{o} = - 0.77 V

F e^{2 +}, F e^{3 +}

F e

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e^{-} \to F e; E_{F e^{2 +} / F e}^{o} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3} / F e^{2 +}}^{o} = + 0.77 V

F e^{2 +} / F e (E^{o} = - 0.44 V), F e^{3 +} / F e^{2 +} (E^{o} = 0.77 V)

F e^{2 +}, F e^{3 +}

F e

F e^{2 +} ⇌ F e; E^{\circ} = - 0.44 V

F e^{3 +} ⇌ F e^{2 +}; E^{\circ} = + 0.77 V

F e^{2 +}, F e^{3 +}

F e

E_{F e^{2 +} | F e}^{⊖}

E_{F e^{3 +} | F e^{2 +}}^{⊖}

F e^{2 +}, F e^{3 +}

F e

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