Given that E O 2 - H 2 O 0-1-23 V - E S 2 O 82- - sO 42-0-2-05 V - E Br 2 - Br -0-1-09 V - E Au 3- - Au 0-1-4 V- The strongest oxidizing agent is-A- O 2B- S 2 O 82-C- Br 2D- Au 3-

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Oxidising Reagent and Reducing Reagent

Given that E ...

Question

Given that $E_{O_{2} / H_{2} O}^{o} = + 1.23 V$ ; $E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{o} = + 2.05 V$ ; $E_{B r_{2} / B r^{-}}^{o} = + 1.09 V$ ; $E_{A u^{3 +} / A u}^{o} = + 1.4 V$ . The strongest oxidizing agent is:

O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S_{2} O_{8}^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A u^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B r_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

E_{O_{2} / H_{2} O}^{o} = + 1.23 V

E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{o} = + 2.05 V

E_{B r_{2} / B r^{-}}^{o} = + 1.09 V

E_{A u^{3 +} / A u}^{o} = + 1.4 V

E_{O_{2} / H_{2} O}^{o} = + 1.23 V;

E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{o} = 2.05 V

E_{B r_{2} / B r^{-}}^{o} = + 1.09 V

E_{A u^{3 +} / A u}^{o} = + 1.4 V

E_{O_{2} / H_{2} O}^{\circ} = + 1.23 V;

E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{\circ} = 2.05 V;

E_{B r_{2} / B r^{⊝}}^{\circ} = + 1.09 V

E_{A u^{3 +} / A u}^{\circ} = + 1.4 V

E_{A u^{+} / A u}^{0}

1.69 V

E_{A u^{3 +} / A u}^{0}

1.40 V

E_{A u^{+} / A u^{3 +}}^{0}

C u^{+}, C o^{3 +}, F e^{2 +}

E_{C u^{2 +} / C u^{+}}^{0} = 0.15 V; E_{C u^{+} / C u}^{0} = 0.53 V E_{C o^{3 +} / C o^{2 +}}^{0} = 1.82 V; E_{F e^{3 +} / F e^{2 +}}^{0} = 0.77 V E_{F e^{2 +} / F e}^{0} = - 0.44 V; E_{O_{2}, H^{+} / H_{2} O}^{0} = 1.23 V

Join BYJU'S Learning Program