Question

Given that $\frac{-6p-9}{3}=\frac{2p+9}{5}$, what is the value of p?

• A. -4
• B. -2
• C. 3
• D. 5

Answer 1

Answer: (B)

Given, $\frac{-6p-9}{3}=\frac{2p+9}{5}$

Solving by cross multiplication,
$\Rightarrow 5(-6p-9)=3(2p+9)$
$\Rightarrow -30p-45=6p+27$
$\Rightarrow -30p-6p=45+27$
$\Rightarrow -36p=72$
$\Rightarrow p=-2$.

Hence, the value of p=$-2$