Given that HCF(2520, 6600) = 60x, LCM (2520, 6600) =252xk, then the value of k is:
Given that HCF (2520, 6600) = 120, LCM (2520, 6600) = 252 k, then the value of k is:
If 635=x100=y1000, find x and y.
Given that HCF(2520,6600)=40LCM(2520,6600)=252×k then find the value of k.