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Question

Given that heat of formation of Ag2O(s), HCl(g) and H2O(l) are 731, 22.06 and 68.32 kcal respectively. Also,
Ag2O+2HCl(s)2AgCl(s)+H2O(l);ΔH=77.61kcal
If heat of formation of AgCl in kcal is x then x/100 is (nearest integer)__________.

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Solution

The expression for the enthalpy change for the reaction is
ΔH=2ΔHf(AgCl)+ΔHf(H2O)[ΔHf(Ag2O)+2ΔHf(HCl)]
Substitute values in the above expression.
77.61kcal=2xkcal68.32kcal(731kcal+2(22.06kcal))
x=392.20kcal
x/100=3.924kcal

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