Question

Given that : $I_2+2e^{-}\to 2I^{-};E_{I_2/I^{-}}^o$ = 0.54V; $B{r}_2+2e^{-}\to 2B{r}^{-};E_{B{r}_2/B{r}^{-}}^o$ = 1.69V. Predict which of the following is true:

• A. $I^{\ominus }$ ions will be able to reduce bromine.
• B. $B{r}^{\ominus }$ ions will be able to reduce iodine.
• C. Iodine will be able to reduce bromine.
• D. Bromine will be able to reduce iodide ions.

Answer 1

The correct option is A $I^{\ominus }$ ions will be able to reduce bromine.

Since the reduction potential of $B{r}_2|2B{r}^{\ominus }$ is greater than the reduction potential of $I_2|2I^{\ominus },so{I}^{\ominus }$ ions will reduce $B{r}_2$ to $B{r}^{-}$.