Given that- i C s - O 2 g - CO 2 g - - H - x kJ ii 2 CO g - O 2 g - 2 CO 2 g - - H - y kJ- The enthalpy offormation of carbon monoxide will be -A- y-2 x - y-2 x-2C- 2 x-y-2D- 2 x-y

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Enthalpy of Neutralisation

Given that: i...

Question

Given that: (i) $C (s) + O_{2} (g) \to C O_{2} (g); Δ H^{\circ} = - x k J$ (ii) $2 C O (g) + O_{2} (g) \to 2 C O_{2} (g); Δ H^{\circ} = - y k J$ . The enthalpy of formation of carbon monoxide will be :

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C (s) + O_{2} (g) \to C O_{2} (g); Δ H^{\circ} = - x k J

2 C O (g) + O_{2} (g) \to 2 C O_{2} (g); Δ H^{\circ} = - y k J

C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94 k c a l

2 C O (g) + O_{2} (g) \to 2 C O_{2} (g); Δ H = - 135.2 k c a l

C O (g)

C_{(s)} + O_{2 (g)} \to C O_{2 (g)}

Δ H = - 393.4 k J

C O_{(g)} + \frac{1}{2} O_{2 (g)} \to C O_{2 (g)}

Δ H = - 283.0 k J

C (s) + O_{2} (g) \to C O_{2} (g), Δ H = - 94

2 C O (g) + O_{2} \to 2 C O_{2} (g), Δ H = - 135.2

C O (g)

C + O_{2} ⟶ C O_{2}; Δ H^{\circ} = - x k J

2 C O + O_{2} ⟶ 2 C O_{2}; Δ H^{\circ} = - y k J

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