Given that: (i) C(s)+O2(g)→CO2(g);ΔH∘=−xkJ (ii) 2CO(g)+O2(g)→2CO2(g);ΔH∘=−ykJ. The enthalpy of formation of carbon monoxide will be :
A
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B
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C
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D
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Solution
The correct option is B Divide equation (ii) by (2) and subtract from equation (i) C(s)+O2(g)→CO2(g);ΔH∘=−xkJ2CO(g)+12O2(g)→CO2(g);ΔH∘=−y2kJC(s)+12O2(g)→CO(g);ΔH∘=−y2x=y−2x2