Given that i -1- i2 -1- i3 -i and i4 -1-The value of i127 is

The correct option is A i i^127 =( i^4)^31× i^3 = (1)^31× ( i) = 1× ( i) = i Option A correct ...

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Adding Consecutive Odd Numbers

Given that ...

Question

Given that $i = \sqrt{- 1}$ , $i^{2} = - 1$ , $i^{3} = - i$ and $i^{4} = 1$ .
The value of $i^{127}$ is

- i

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(1 + i + i^{2} + i^{3} + i^{4} + i^{5}) (1 + i) =

1 + (1 + i) + (1 + i)^{2} + (1 + i)^{3} =

\frac{1}{i} + \frac{1}{i^{2}} + \frac{1}{i^{3}} + . . . . + \frac{1}{i^{102}}

a = 1 + i^{2} + i^{4} + \dots + i^{2 n}

b = {cos}^{- 1} (∣ ∣ ∣ \frac{1}{1 + i} ∣ ∣ ∣)

i = \sqrt{- 1}

tan (\frac{b}{a})

The value of i + $i^{2}$ + $i^{3}$ + $i^{4}$ is __

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