1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Sin(A+B)Sin(A-B)
Given that ...
Question
Given that
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
.
.
.
.
(
1
+
tan
45
∘
)
=
2
∘
,
find n.
Open in App
Solution
Given that:
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
.
.
.
.
.
.
.
.
(
1
+
tan
45
∘
)
=
2
n
LHS,
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
.
.
.
.
.
.
.
.
(
1
+
tan
45
∘
)
−
(
A
)
we know that
tan
(
A
+
B
)
=
tan
A
+
tan
B
1
−
tan
A
.
tan
B
,
also,
tan
45
∘
=
1
So,
tan
45
∘
=
tan
1
∘
+
tan
44
∘
1
−
tan
1
∘
.
tan
44
∘
⇒
tan
1
∘
+
tan
44
∘
−
(
1
−
tan
1
∘
.
tan
44
∘
)
(
tan
45
∘
)
−
(
i
)
tan
45
∘
=
tan
2
∘
+
tan
43
∘
1
−
tan
2
∘
.
tan
43
∘
⇒
tan
2
∘
+
tan
43
∘
−
(
1
−
tan
2
∘
.
tan
43
∘
)
(
tan
45
∘
)
−
(
i
i
)
.
.
.
.
tan
45
∘
=
tan
22
∘
+
tan
23
∘
1
−
tan
22
∘
.
tan
23
∘
⇒
tan
22
∘
+
tan
23
∘
−
(
1
−
tan
22
∘
.
tan
23
∘
)
(
tan
45
∘
)
−
(
22
)
Using the above equation we can simplify the expression
(
A
)
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
(
1
+
tan
3
∘
)
.
.
.
.
.
.
.
.
(
1
+
tan
44
∘
)
(
1
+
tan
45
∘
)
=
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
(
1
+
tan
3
∘
)
.
.
.
.
.
.
.
.
(
1
+
tan
44
∘
)
×
2
=
2
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
(
1
+
tan
3
∘
)
.
.
.
.
.
.
.
.
(
1
+
tan
44
∘
)
=
2
(
1
+
tan
1
∘
)
(
1
+
tan
44
∘
)
(
1
+
tan
2
∘
)
(
1
+
tan
43
∘
)
(
1
+
tan
3
∘
)
(
1
+
tan
42
∘
)
.
.
.
.
.
(
1
+
tan
22
∘
)
(
1
+
tan
23
∘
)
=
2
(
tan
1
∘
+
tan
44
∘
+
tan
1
.
tan
44
+
1
)
(
tan
2
∘
+
tan
43
∘
+
tan
2
∘
.
tan
43
∘
+
1
)
.
.
.
.
.
.
.
(
tan
22
∘
+
tan
23
∘
+
tan
22
∘
.
tan
23
∘
+
1
)
=
2
[
(
tan
45
∘
)
(
1
−
tan
1
∘
.
tan
44
∘
+
tan
1
∘
.
tan
44
∘
+
1
)
(
tan
45
∘
(
1
−
tan
2
∘
.
tan
43
∘
)
+
tan
2
∘
.
tan
43
∘
+
1
)
.
.
.
.
.
.
.
(
tan
45
∘
(
1
−
tan
22
∘
.
tan
23
∘
)
+
tan
22
∘
.
tan
23
∘
+
1
)
]
=
2
[
(
1
−
tan
1
∘
.
tan
44
∘
+
tan
1
∘
.
tan
44
∘
+
1
)
(
1
−
tan
2
∘
.
tan
43
∘
+
tan
2
∘
.
tan
43
∘
+
1
)
.
.
.
.
.
.
.
(
1
−
tan
22
∘
.
tan
23
∘
+
tan
22
∘
.
tan
23
∘
+
1
)
]
=
2.
(
2
)
.
(
2
)
.
.
.
.
.
.
.
.
.
.
(
2
)
=
2.
2
22
=
2
23
∴
n
=
23
Suggest Corrections
0
Similar questions
Q.
If
(
1
+
tan
1
∘
)
⋅
(
1
+
tan
2
∘
)
⋅
(
1
+
tan
3
∘
)
…
⋅
(
1
+
tan
45
∘
)
=
2
n
, then
′
n
′
is equal to ?
Q.
If
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
.
.
.
.
.
.
.
.
(
1
+
tan
45
∘
)
=
2
n
,
then
n
is
Q.
The value of
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
…
(
1
+
tan
45
∘
)
is
Q.
The value of
A
=
(
1
+
tan
1
∘
)
(
1
+
tan
2
∘
)
(
1
+
tan
3
∘
)
⋯
(
1
+
tan
45
∘
)
is
Q.
The value of
(
1
+
t
a
n
1
∘
)
(
1
+
t
a
n
2
∘
)
(
1
+
t
a
n
3
∘
)
.
.
.
.
(
1
+
t
a
n
45
∘
)
=
L
M
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Transformations
MATHEMATICS
Watch in App
Explore more
Sin(A+B)Sin(A-B)
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app