Given that log102=0.3010, the number of digits in the number 20002000 is
A
6600
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B
6603
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C
6543
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D
2345
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Solution
The correct option is B6603 Let x=20002000 ⇒log10x=2000log102000 ⇒log10x=2000log10(2×1000) ⇒log10x=2000(log102+log101000) ⇒log10x=2000(0.3010+3) ⇒log10x=2000(3.3010)=6602