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Law of Mass Action

Given that on...

Question

Given that one mole of $N_{2}$ at NTP occupies $22.4$ litre the density of $N_{2}$ is :

A

1.25 g / L

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B

0.80 g / L

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C

2.5 g / L

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D

1.60 g / L

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Solution

The correct option is A $1.25 g / L$
Weight of one mole $N_{2} = 28 g$
Volume of one mole $N_{2} = 28 g$ at NTP = 22.4 Lit
D = $\frac{W}{V} = \frac{28}{22.4} = 1.25 \frac{g}{L}$

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