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Question

Given that a=^i+^j+^k,c=^j^k and a.b=3,a×b=c then 3b=

A
5^i+2^j+2^k
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B
5^i2^j2^k
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C
5^i+2^j+2^k
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D
None of these
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Solution

The correct option is C 5^i+2^j+2^k
a×b=c
a×(a×b)=a×c
(a.b)a(a.a)b=a×c
3(^i+^j+^k)3b=∣ ∣ ∣^i^j^k111011∣ ∣ ∣
3b=3(^i+^j+^k){(11)^j(1)+^k(1)}
3b=3^i+3^j+3^k+2^i^j^k
3b=5^i+2^j+2^k

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