Given that →C=→A+→B. The magnitude of →A,→B and →C are 12, 5 and 13 units respectively. The angle between →A and →B is
A
0∘
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B
π4
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C
π2
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D
π
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Solution
The correct option is Cπ2 If →C=→A+→B, then magnitude of →C and →A+→B are same |→C|=|→A+→B| |→C|=√A2+B2+2ABcosθ13=√122+52+2×12×5cosθ ⇒169=144+25+2×12×5cosθcosθ=0⇒θ=π2