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Question

Given that (p+3) is the highest common factor of 81 and 108, find the value of p.


A

6

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B

12

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C

9

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D

24

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Solution

The correct option is D

24


Prime factorisation of 81 and 108:

81 = 3 × 3 × 3 × 3
108 = 2 × 2 × 3 × 3 × 3

The highest common factors is 3 × 3 × 3 = 27

Given, HCF of 81 and 108 is (p+3).
p+3=27
p=24


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