Given that (p+3) is the highest common factor of 81 and 108, find the value of p.
24
Prime factorisation of 81 and 108:
81 = 3 × 3 × 3 × 3
108 = 2 × 2 × 3 × 3 × 3
∴ The highest common factors is 3 × 3 × 3 = 27
Given, HCF of 81 and 108 is (p+3).
∴p+3=27
⇒p=24