Given that S -3-2 O 2- SO 3-2 x kcal andSO 2-1-2 O 2- SO 3- y kcal then- the enthalpy of formation of SO 2 will be-A- x - y kcal mol -1B- 2 x - y k calmol -1C- x - y kcal mol -1D- y-2 x kcal mol -1

The correct option is D (y 2x) kcal mol^ 1S + 32O_2 → SO_3 ; Δ H= 2x kcal…… (i) SO_2 + 12O_2 → SO_3 ; Δ H= y kcal…… (ii) Reversing the eqn (2), we get ...

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Byju's Answer

Standard XII

Chemistry

Hess' Law

Given that S ...

Question

Given that
$S + \frac{3}{2} O_{2} \to S O_{3} + 2 x kcal$ and
$S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y kcal$ then, the enthalpy of formation of $S O_{2}$ will be:

(2 x + y) {kcalmol}^{- 1}

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(x - y) {kcal mol}^{- 1}

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(x + y) {kcal mol}^{- 1}

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(y - 2 x) {kcal mol}^{- 1}

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Solution

The correct option is D $(y - 2 x) {kcal mol}^{- 1}$
$S + \frac{3}{2} O_{2} \to S O_{3}; Δ H = - 2 x kcal \dots \dots (i)$
$S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - y kcal \dots \dots (i i)$
Reversing the eqn (2), we get
$S O_{3} \to S O_{2} + \frac{1}{2} O_{2}; Δ H = + y kcal \dots \dots (i i i)$

Adding equation (i) and (iii),
$S + O_{2} \to S O_{2}; Δ H = (y - 2 x) kcal$

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Similar questions

Q. In the reaction : S + 3/2

O_{2} \to S O_{3}

+ 2x kcal and

S O_{2} + 1 / 2 O_{2} \to S O_{3}

+ y kcal, heat of formation of

S O_{2}

is:

In the reaction

$S + \frac{3}{2} O_{2} \to S O_{3} + 2 x k J$ and $S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y k J$

Heat of formation of $S O_{2}$ is

S + \frac{3}{2} O_{2} ⟶ S O_{3} + 2 x k c a l

;

S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3} + y k c a l

;

The heat of formation of

S O_{2}

is :

Q. In the reactions

S + \frac{3}{2} O_{2} \to S O_{3} + 2 x k c a l

and

S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y k c a l

, the heat of formation of

S O_{2}

is :

Q. Given:

S + \frac{3}{2} O_{2} ⟶ S O_{3} + 2 x

k c a l

S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3} + y

k c a l

With the help of the above reactions, find out the heat of formation of

S O_{2}

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Given that S+32O2→SO3+2x kcal and SO2+12O2→SO3+y kcal then, the enthalpy of formation of SO2 will be:

The correct option is D (y−2x) kcal mol−1S+32O2→SO3 ; ΔH=−2x kcal……(i) SO2+12O2→SO3 ; ΔH=−y kcal……(ii) Reversing the eqn (2), we get SO3→SO2+12O2 ; ΔH=+y kcal……(iii) Adding equation (i) and (iii), S+O2→SO2 ; ΔH=(y−2x) kcal

Given that
$S + \frac{3}{2} O_{2} \to S O_{3} + 2 x kcal$ and
$S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y kcal$ then, the enthalpy of formation of $S O_{2}$ will be: