Question

Given that $\sec \theta +\tan \theta =1$ then one root of the equation $(a-2b+c)x^2+(b-2c+a)x+(c-2a+b)=0$ is

• A. $\sec \theta$
• B. $\tan \theta$
• C. $\sin \theta$
• D. $\cot \theta$

Answer 1

The correct option is A $\sec \theta$

$\sec \theta +\tan \theta =1$
simplest $\theta$ that satisfies this is $\theta =0$
so $\sec \theta =1$
clearly this satisfies the given equation