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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios for Sum of Two Angles
Given that ...
Question
Given that
sin
α
=
√
3
2
,
cos
β
=
√
3
2
find the value of
(
α
−
β
)
.
Open in App
Solution
sin
α
=
√
3
2
,
cos
β
=
√
3
2
w
e
k
n
o
w
t
h
a
t
⇒
sin
α
=
sin
π
3
∴
α
=
π
/
3
⇒
a
n
d
s
i
m
i
l
a
r
l
y
⇒
cos
β
=
√
3
2
⇒
cos
β
=
π
6
∴
β
=
π
/
6
T
h
e
n
,
v
a
l
u
e
o
f
α
−
β
=
π
3
−
−
π
6
=
π
6
A
n
s
.
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Similar questions
Q.
If
sin
α
=
12
/
13
(
0
<
α
<
π
/
2
)
and
cos
β
=
−
3
5
(
π
<
β
<
3
2
π
)
, the value of
sin
(
α
+
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)
is
Q.
If
α
,
β
,
γ
ϵ
[
0
,
2
π
]
, then sum of all positive values of
α
,
β
,
γ
if,
sin
α
=
−
1
√
2
,
cos
β
=
−
1
2
,
tan
γ
=
−
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, is
Q.
Given that
sin
α
=
1
2
and
cos
β
=
1
2
, then the value of
(
α
+
β
)
is:
Q.
If
sin
α
−
sin
β
=
1
/
3
and
cos
β
−
cos
α
=
1
/
2
,
then
cot
α
+
β
2
=
k
3
. Find the value of
k
.
Q.
cos
(
α
−
β
)
+
cos
(
β
−
γ
)
+
cos
(
γ
−
α
)
=
−
3
2
then prove that
cos
α
+
cos
β
+
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γ
=
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α
+
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β
+
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γ
=
0
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Standard XII Mathematics
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