Given that sinA - 1-2 and cosB - 1-2- then the value of A - B is -Here- 0 - A - B - 90-

Given that, nbsp; sinA = 1/2 nbsp;and cosB = 1/√(2) —— (i) We know that, nbsp; sin30^o = 1/2 nbsp;and cos45^o = 1/√(2) —— (ii) [ From Trigonometric R ...

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Standard XII

Mathematics

AM,GM,HM Inequality

Given that si...

Question

Given that $s i n A = \frac{1}{2}$ and $c o s B = \frac{1}{\sqrt{2}}$ , then the value of $(A + B)$ is ___________.
(Here, 0 < A + B ≤ 90°)

45°

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30°

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15°

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75°

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Solution

The correct option is D
75°

Given that,
$s i n A = \frac{1}{2}$ and $c o s B = \frac{1}{\sqrt{2}}$ ------- (i)

We know that,
$s i n 30^{o} = \frac{1}{2}$ and $c o s 45^{o} = \frac{1}{\sqrt{2}}$ ------- (ii)
[ From Trigonometric Ratios ]

On comparing (i) and (ii)
We get, A = $30^{o}$ and B = $45^{o}$

Therefore, $(A + B) = 30^{o} + 45^{o} = 75^{o}$

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Given that sinA=12 and cosB=1√2, then the value of (A+B) is ___________. (Here, 0 < A + B ≤ 90°)

The correct option is D 75° Given that, sinA=12 and cosB=1√2 ------- (i) We know that, sin30o=12 and cos45o=1√2 ------- (ii) [ From Trigonometric Ratios ] On comparing (i) and (ii) We get, A = 30o and B = 45o Therefore, (A+B)=30o+45o=75o

Given that $s i n A = \frac{1}{2}$ and $c o s B = \frac{1}{\sqrt{2}}$ , then the value of $(A + B)$ is ___________.
(Here, 0 < A + B ≤ 90°)