Question

Given that $\sqrt{3}=1.732$, then the value of $\sqrt{75}+\frac{1}{2}\sqrt{48}-\sqrt{192}$$=-1.732$.

• A. True
• B. False

Answer 1

The correct option is A True

Given,$\sqrt{3}=1.732$.

Then the value of $\sqrt{75}+\frac{1}{2}\sqrt{48}-\sqrt{192}$
$=\sqrt{25\times 3}+\frac{1}{2}\sqrt{16\times 3}-\sqrt{64\times 3}$
$=5\sqrt{3}+\frac{1}{2}\times 4\sqrt{3}-8\sqrt{3}$
$=5\sqrt{3}+2\sqrt{3}-8\sqrt{3}$
$=7\sqrt{3}-8\sqrt{3}$
$=-\sqrt{3}=-1.732$.

That is, $\sqrt{75}+\frac{1}{2}\sqrt{48}-\sqrt{192}$ $=-1.732$.

Hence, the statement is true and option $A$ is correct.