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Question

Given that nx=1(x+1)(2x+3) = pn4+qn3+rn2+73n+s, then

i)p=12,q=83 ii)p=13,q=14 iii)r=92,s=0 iv)r=56,s=0

A

I and IV only

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B

II and III only

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C

I and III only

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D

I,II,III,IV

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Solution

The correct option is C

I and III only


Put n = 1, x = 1
Then LHS = (1+1)× (2+3) = 10
RHS = p+q+r+73+s should = 10
Plug in all possible answer values
Options I and III give the right answer as 12+83+92+73=10


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