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Question

Given that the abundances of isotopes 54Fe , 56Fe and 57Fe are 5 % , 90 % and 5%.

Respectively,the atomic mass of Fe is


A

55.85

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B

55.95

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C

55.75

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D

56.05

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Solution

The correct option is B

55.95


Average atomic mass of Fe

= (54×4)+(56×90)+(57×5)100 = 55.95


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