Given that the displacement of an oscillating particle is given by $y = A sin[Bx + Ct + D]$ . The dimension formula for ABCD is (where x is displacement and t is time)

$[M^{0} L^{- 1} T^{0}]$

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$[M^{0} L^{0} T^{- 1}]$

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$[M^{0} L^{- 1} T^{- 1}]$

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$[M^{0} L^{0} T^{0}]$

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Solution

The correct option is B
$[M^{0} L^{0} T^{- 1}]$

$A = L, B = L^{- 1}, C = T^{- 1}$ and $D = M^{0} L^{0} T^{0}$

$[ABCD] = [M^{0} L^{0} T^{- 1}]$

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Given that the displacement of an oscillating particle is given by y=A sin[Bx + Ct + D]. The dimension formula for ABCD is (where x is displacement and t is time)

The correct option is B [M0L0T−1] A = L, B = L−1, C=T−1 and D=M0L0T0 [ABCD]=[M0L0T−1]

Given that the displacement of an oscillating particle is given by $y = A sin[Bx + Ct + D]$ . The dimension formula for ABCD is (where x is displacement and t is time)

The correct option is B
$[M^{0} L^{0} T^{- 1}]$

$A = L, B = L^{- 1}, C = T^{- 1}$ and $D = M^{0} L^{0} T^{0}$

$[ABCD] = [M^{0} L^{0} T^{- 1}]$