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Question

Given that the equilibrium constant for the reaction, 2SO2(g)+O2(g)2SO3(g), has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?


SO3(g)SO2(g)+12O2(g)

A
3.6×103
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B
6.0×102
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C
1.3×105
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D
1.8×103
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Solution

The correct option is B 6.0×102
2SO2(g)+O2(g)2SO3(g), K=278 ....(i)

By reversing the equation (i), we get

2SO3(g)2SO2(g)+O2(g) .....(ii)

Equilibrium constant for this reaction is
K=1K=1/278

By dividing the equation (ii) by 2, we get the desired equation.

SO3(g)SO2(g)+1/2O2(g) .....(iii)

The equilibrium constant for this reaction

K =(1K)1/2

K=5.99×102

So, B option is correct.

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