Given that the $N$ shell of an element contains 10 electrons, write the electronic configuration of the stable ion.

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Solution

The electronic configuration of Ni.
The total number of electrons in the element $=$ the number of electrons in $K + L + M + N$ shells i.e. $2 + 8 + 8 + 10 = 28$ .
So, atomic no. of element is 28 (Nickel).
The electronic state of a stable ion $N i^{2 +} = 2, 8, 8, 8$

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Given that the N shell of an element contains 10 electrons, write the electronic configuration of the stable ion.

The electronic configuration of Ni.The total number of electrons in the element = the number of electrons in K+L+M+N shells i.e. 2+8+8+10=28. So, atomic no. of element is 28 (Nickel).The electronic state of a stable ion Ni2+=2,8,8,8

Given that the $N$ shell of an element contains 10 electrons, write the electronic configuration of the stable ion.

The electronic configuration of Ni.
The total number of electrons in the element $=$ the number of electrons in $K + L + M + N$ shells i.e. $2 + 8 + 8 + 10 = 28$ .
So, atomic no. of element is 28 (Nickel).
The electronic state of a stable ion $N i^{2 +} = 2, 8, 8, 8$