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Question

Given that the relative molecular mass [molecular weight] of copper oxide is 80, what volume of ammonia [measured at s.t.p] is required to completely reduce 120 g of copper oxide.
The equation for the reaction is : 3CuO+2NH33Cu+3H2O+N2.

A
44.8L
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B
5.56L
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C
11.2L
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D
22.4L
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Solution

The correct option is D 22.4L
3CuO+2NH33Cu+3H2O+N2

3 mole 2 mole

3×80 g 2×22.4 L

= 240 g = 44.8 lit

For 240g of CuO, ammonia consumed is 44.8L

For 120gof CuO, ammonia consumed = 44.82= 22.4L


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