Given that the standard potential (E∘) of Cu2+/Cu and Cu+/Cu are 0.340V and 0.522V respectively. The E∘ of Cu2+/Cu+ is:
A
−0.182V
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B
−0.158V
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C
+0.158V
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D
0.182V
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Solution
The correct option is C+0.158V Cu2++2e−→CuE∘=0.340V Cu→Cu++e−E∘=−0.522V Cu2++e−→Cu+E∘=?
Applying ΔG=−nFE∘
We get, (−1×F×E∘)=(−2×F×0.340)+(−1×F×−0.522)
Solving, we get, E∘=0.158V