Question

Given that the two numbers appearing on throwing two dice are different. Find the probability of the event that the sum of numbers on the dice is 4.

Answer 1

Number of Possible outcomes ${}^6{P}_2=\frac{6!}{4!}=30$

Number of favourable outcomes $\{1,3\},\{2,2\},\{3,1\}=3$

Probabilty is given as $\frac{3}{30}=\frac{1}{10}$