Given that, three consecutive terms of an A.P. are the lengths of the sides of the triangle. If the perimeter of the triangle is 6 m, find the middle term of the three consecutive terms.
2m
Let the three consecutive terms of the A.P. be a - d, a and a + d.
Perimeter = a - d + a + a + d = 6
So, 3a = 6 ⇒ a = 2
So, the middle term = a = 2 m