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Depression in Freezing Point

Given that T ...

Question

Given that $△ T_{f}$ if is the diperssion in freezing point of the solvent of non-volatile solute of molality m, the quantity $l i m m \to 0 (\frac{△ T_{f}}{m}) i s e q u a l t o$

Zero

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One

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∞

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Finite value

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Solution

The correct option is D Finite value
$△ T_{f} = K_{f} m$
$l i m m \to 0 (\frac{△ T_{f}}{m}) = l i m m \to 0 (K_{f}) = K_{f}$

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Similar questions

△ T_{f}

l i m m \to 0 (\frac{△ T_{f}}{m}) i s e q u a l t o

Δ T_{f}

lim m \to 0 (Δ T_{f} / m)

240^{\circ} C

0.25

3^{\circ} C

K_{f}

{K kg mol}^{- 1}

{100.15}^{\circ} C

k_{b}

k_{f}

0.512

1.86 K {molality}^{- 1}

101^{\circ} C .

(K_{f} = {1.86}^{\circ} C / m

K_{b} = {0.51}^{\circ} C / m)

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