Given that A- and B- are greater than one- then the magnitude of A-B- can not be

The correct option is D more than |A⃗||B⃗ | Magnitude of A× B can never exceed A⃗B⃗ as it is ABsinθ and sinθ is always less than ...

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General Solution of Trigonometric Equation

Given that ...

Question

Given that $\to A$ and $\to B$ are greater than one, then the magnitude of $(\to A \times \to B)$ can not be

equal to

\to A \to B

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less than

\to B

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more than

∣ \to A ∣∣ \to B |

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equal to

\to A / \to B

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Solution

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Similar questions

\to A B = \to a, \to B C = \to b

\to A B = \to a, + \to b

\to B D = \to b, - \to a

| \to a | = 2

| \to b | = 3

\to a \to b = 0

(\to a \times (\to a \times (\to a \times (\to a \times \to b))))

{(\to a \times \to b) \times \to a} \times \to b + \to a \times {\to b \times (\to a \times \to b)}

\to a

\to b

(\to a + \to b) \cdot (\to a + \to b) = {| \to a |}^{2} + {∣ ∣ \to b ∣ ∣}^{2}

\to a \to b

\to a \neq \to 0, \to b \neq \to 0

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