Given that x -2 p and y -4 q- then value of log 2 x 3 y isA- 3 p -2 qB- 2 p -3 q- 3 p - qD- p -3 q

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Introduction

Given that x ...

Question

Given that $x = 2^{p}$ and $y = 4^{q}$ , then value of ${log}_{2} (x^{3} y)$ is

3 p + 2 q

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2 p + 3 q

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3 p + q

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p + 3 q

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Solution

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Similar questions

x = \frac{{sin}^{3} p}{{cos}^{2} p}, y = \frac{{cos}^{3} p}{{sin}^{2} p}

sin p + cos p = \frac{1}{2}

x + y

∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 + p & 1 + p + q 2 & 3 + 2 p & 4 + 3 p + 2 q 3 & 6 + 3 p & 10 + 6 p + 3 q \end{matrix} ∣ ∣ ∣ ∣

\frac{2 p}{3 p} = \frac{4 k}{6 k} = \frac{2 p + 8 q}{3 p + 12 q}

¯ ¯ ¯ r = 3 ¯ ¯ ¯ p + 4 ¯ ¯ ¯ q

2 ¯ ¯ ¯ r = ¯ ¯ ¯ p - 3 ¯ ¯ ¯ q

∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 + p & 1 + p + q 2 & 3 + 2 p & 4 + 3 p + 2 q 3 & 6 + 3 p & 10 + 6 p + 3 q \end{matrix} ∣ ∣ ∣ ∣

= 1

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