CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

Given that x2+x6 is a factor of 2x4+x3ax2+bx+a+b1, then find the values of a and b.

A
a=16,b=3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a=16,b=2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a=10,b=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C a=16,b=3
As x2+x6=(x+3)(x2)
Let f(x)=2x4+x3ax2+bx+a+b1
We get
f(3)=2(3)4+(3)3a(3)2+b(3)+a+b1=0
1348a2b=04a+b=67 (1)
And
f(2)=2(2)4+23a(2)2+2b+a+b1=0
393a+3b=0ab=13(2)
Solving (1) and (2), we get
a=16,b=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon