Given that x- y and b are real numbers and x0-then

The correct option is A x/b lt;y/b It is given that,x lt;y,b lt;0 x/b gt;y/b [∵ b lt;0] ...

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Inequality

Given that x,...

Question

Given that x,y and b are real numbers and x<y,b>0,then

$\frac{x}{b} < \frac{y}{b}$

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$\frac{x}{b} \leq \frac{y}{b}$

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$\frac{x}{b} > \frac{y}{b}$

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$\frac{x}{b} \geq \frac{y}{b}$

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Solution

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\frac{x}{b < \frac{y}{b}}

\frac{x}{b \leq \frac{y}{b}}

\frac{x}{b > \frac{y}{b}}

\frac{x}{b \geq \frac{y}{b}}

x_{0}, y_{0}

x_{0}^{2} + y_{0}^{2} > 1

x, y

x^{2} + y^{2} \leq 1

(x - x_{0})^{2} + (y - y_{0})^{2}

x + y + z = a

x, y, z

x = c y

y = a z + c x

z = b x + a y

a^{2} + b^{2} + c^{2} + 2 a b c

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