Given that y = -6x + 1 and $- 3 < x < \frac{2}{3}$ .
Then, in which of the following intervals does the value of y lie?

(18, -4)

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(3, 19)

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(-19, 3)

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(-3,19)

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Solution

The correct option is D (-3,19)
Given that,
$- 3 < x < \frac{2}{3}$ .

$- 3 (- 6) > x . (- 6) > \frac{2}{3} (- 6) .$
$18 > - 6 x > - 4$

Now adding 1 to the inequality, we get
19 > -6 x + 1 > - 3

i.e., 19 > y > -3

Thus, $y \in (- 3, 19)$

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