Given that- Zn-1-2O2- ZnO-35-25 KJ HgO- Hg-1-2O2-9-11 KJThe heat of the reaction Zn-HgO- ZnO-Hg is

The correct option is B 26.14 KJ Zn+1/2O_2→ ZnO; Δ H= 35.25 KJ HgO→ Hg+1/2O_2; Δ H=9.11 KJ Zn+HgO→ ZnO+Hg; Δ H= 35.25 KJ+9.11 KJ = 26.14 K ...

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Given that, ...

Question

Given that,
$Z n + \frac{1}{2} O_{2} \to Z n O + 35.25 K J$
$H g O \to H g + \frac{1}{2} O_{2} - 9.11 K J$
The heat of the reaction $Z n + H g O \to Z n O + H g$ is

-26.14 KJ

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44.39 KJ

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-44.39 KJ

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26.14 KJ

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Solution

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Similar questions

Z n + 1 / 2 O_{2} \to Z n O + 35.25 k J . H g O \to H g + 1 / 2 O_{2} + 9.11 k J .

Z n + H g O \to Z n O + H g

Z n + \frac{1}{2} O_{2} \to Z n O Δ H = + 84000 c a l

H g + \frac{1}{2} O_{2} \to H g O Δ H = + 21700 c a l

(Δ H)

Z n + H g O \to Z n O + H g

1000^{\circ} C

i . Z n (s) + \frac{1}{2} O_{2} (g) \to Z n O (s); Δ G = - 360 KJ/mol

i i . C (s) + \frac{1}{2} O_{2} (g) \to C O (s); Δ G = - 460 KJ/mol

Zn is the oxidant in the following reaction

$Z n (s) + \frac{1}{2} O_{2} ⟶ Z n O (s)$

C (g r a p h i t e) + \frac{1}{2} O_{2} \to C O Δ H_{1} = - 110.5 k J / m o l

C O + \frac{1}{2} O_{2} \to C O_{2} Δ H = - 283.2 k J / m o l

k J / m o l

C (g r a p h i t e) + O_{2} \to C O_{2} Δ H = ?

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