Given the circle at the right with diameter $¯ ¯¯¯¯¯¯ ¯ A B$ find x

30^{\circ}

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45^{\circ}

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60^{\circ}

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90^{\circ}

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Solution

The correct option is D $90^{\circ}$
We know that the angle subtended by the diameter at the circumference is a right angle.
Here, AB is the diameter and it subtends an angle at the circumference.
Thus,
$∠ x = 90^{0}$

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Similar questions

In the given figure, AB is the diameter of the circle. AC is equal to BC. Find the value of $∠ A B C$ .

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