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Question

Given the data at 25oC,


Ag(s)+I(aq)AgI(s)+e,Eo=0.152V

Ag(s)Ag+(aq)+e,Eo=0.800V

What is the value of log Ksp for AgI?
(Where Ksp=solubility product,2.303RTF=0.059V).

A
8.12
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B
+8.612
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C
3783
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D
16.13
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Solution

The correct option is C 16.13
AgI(s)+eAg(g)+I ; Eo=0.192

Ag(s)Ag++e ; Eo=0.8

AgI(s)Ag++I ; Eo=0.952
Ecell=0

Eocell=0.059nlogk

0.952=0.0591logksp

logksp=0.9520.059=16.135

Value of logksp=16.135 .

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